Graph x=y^22y1 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabolaSimple and best practice solution for 2xy(4y^2)dx(y1)(x^22)dy=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homeworkSteps for Solving Linear Equation y=2x1 y = 2 x − 1 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2x1=y 2 x − 1 = y Add 1 to both sides Add 1 to both sides
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(1-y^2)(1+log x)dx+2xy dy=0-X and y are positive integers;Answer to Solve this differential equation dy/dx = 1 2xy/x^2 1 Solve this differential equation (2x 1/y) dx (x^2 1/y)
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PreAlgebra Examples Expand (x−y)(x2 −2xyy2) ( x y) ( x 2 2 x y y 2) by multiplying each term in the first expression by each term in the second expression Simplify each term Tap for more steps Multiply x x by x 2 x 2 by adding the exponents2xy dx (x^2 1) dy =0 => 2xydx = (x^2–1)dy => 2x/(x^2–1)dx = dy/y after integrating both sides => ln(x^2–1) = ln(y) constant => ln(x^2–1)ln(ySimplify x/ (xy) (2x)/ (xy) (2xy)/ (x^2y^2) x x − y − 2x x y − 2xy x2 − y2 x x y 2 x x y 2 x y x 2 y 2 Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (ab)(a−b) a 2 b 2 = ( a b) ( a b) where a = x a = x and b = y b = y
See the answer Show transcribed image text Expert Answer Previous question Next question Transcribed Image Text from this Question (x^2 1) y' 2xy^2 = 0, y(0) = 1 Get more help from Chegg Solve it with our calculus problem solver and calculatorEquations Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations (2xy)/(x^2y^21) so that you understand betterMath Input NEW Use textbook math notation to enter your math Try it
Equivalent to ( y 2 y 1) 2 = 1 c 2 1 − x 2 c ≠ 0 Solving for y leads to y = 1 − 2 c 1 − x 2 The equation remains valid for c = 0 according to the particular solution y ( x) = − 1 2 which can be checked directly in the original ODEY'' 2xy = 0 Natural Language; Find an answer to your question Solve (X^22xyy^2)(x1) 10Admission to the Carnival is $4 Each game played costs an additional $2
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Active Oldest Votes 1 Lets x = α x ~ and y = β y ~ Then, 2 x y y ′ = x 2 − y 2 2 x ~ y ~ y ~ ′ = ( α β) 2 x ~ 2 − y ~ 2 The equation is invariant under the above scaling whenever α = ± β It means, x x ~ = ± y y ~ y ~ x ~ = ± y x It suggests the change of variables u ≡ y x y = u xSteps Using the Quadratic Formula = { x }^ { 2 } { y }^ { 2 } 2xy1=0 = x 2 y 2 − 2 x y − 1 = 0 All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions, one when ± is addition and one when it is subtractionPlot 3x^22xyy^2=1 WolframAlpha Assuming "plot" is a plotting function Use as referring to geometry
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X3yx2y2xy=0 Four solutions were found x = 2 x = 1 y = 0 x = 0 Step by step solution Step 1 Step 2 Pulling out like terms 21 Pull out like factors x3y x2y Consider x^ {2}2xy3y^ {2} as a polynomial over variable x Find one factor of the form x^ {k}m, where x^ {k} divides the monomial with the highest power x^ {2} and mSo we have an equation of the form, mathM(x,y)\text{d}xN(x,y)\text{d}y=0/math Where mathM=(xy)^2,N=(2xyx^21)/math Thus this is an exact differentialClick here👆to get an answer to your question ️ The solution of dy/dx = x^2 y^2 1/2xy satisfying y(1) = 1 is given by
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And x>y Math Factorize a^2 1 2b b^2 Calculus The line that is normal to the curve x^2=2xy3y^2=0 at(1,1) intersects the curve at whatThis is almost certainly a problem in a section of the text on "exact" equations, ie ones of the form dF= F,x dx F,y dy =0 The solution is F(x,y)=constant You need to look for an integrating factor A such that F,x = A 2 x y F,y = A (x^2 y^2The following identity can be used to find Pythagorean triples, where the expressions x2−y2, 2xy, and x2y2 represent the lengths of three sides of a right triangle;
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Simple and best practice solution for x^2y^22xy2x2y1=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homeworkAnswer to Factor 1(x^2y^2)2xy By signing up, you'll get thousands of stepbystep solutions to your homework questions You can also askGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
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Question (x^2 1) Y' 2xy^2 = 0, Y(0) = 1 This problem has been solved!X 2 2xy y 2 (—— ———) —— a 2 ab b 2 Step 4 Calculating the Least Common Multiple 41 Find the Least Common Multiple The left denominator is a 2 The right denominator is ab Number of times each Algebraic Factor appears in the factorization of(2) (4 pts) Find the integral F ds, Jc where C is the curve parametriza x(t) = 2cost, y(t) = sint, z(t) =t, 0<t<2x
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Tap for more steps Add 1 1 to both sides of the equation x 2 y 2 2 x 2 y = 1 x 2 − y 2 − 2 x − 2 y = 1 Complete the square for x 2 2 x x 2 − 2 x Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = 2, c = 0 a = 1, b = − 2, c = 0For the differential equation `(x^2y^2)dx2xy dy=0`, which of the following are true (A) solution is `x^2y^2=cx` (B) `x^2y^2=cx` `x^2y^2=xc` (D) `yExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music
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Factor out the Greatest Common Factor (GCF), '4x 2 y' 4x 2 y(1 2xy x 2) = 0 Ignore the factor 4 Subproblem 1 Set the factor 'x 2 y' equal to zero and attempt to solve Simplifying x 2 y = 0 Solving x 2 y = 0 Move all terms containing x to the left, all other terms to the right Simplifying x 2 y = 0 The solution to this equation could not be determined This subproblem is being ignoredFind a series solution about the point x=0 of (1x^2)y"2xy'2y=0Dividing by math(1x^2)/math both sides in given equation math\dfrac{dy}{dx}\dfrac{2x}{(1x^2)}\cdot y=\dfrac{x(1x^2)}{(1x^2)}/math Now comparing with
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Algebra Factor x^22xyy^2 x2 2xy y2 x 2 2 x y y 2 Check that the middle term is two times the product of the numbers being squared in the first term and third term 2xy = 2 ⋅x⋅y 2 x y = 2 ⋅ x ⋅ y Rewrite the polynomial x2 2⋅x⋅yy2 x 2 2 ⋅ x ⋅ y y 212 x 2 2xy y 2 is a perfect square It factors into (xy)•(xy) which is another way of writing (xy) 2 How to recognize a perfect square trinomial • It has three terms • Two of its terms are perfect squares themselves • The remaining term is twice the product of the square roots of the other two terms Final result (x y) 2Gradient x^2y^22xy, \at (1,2) \square!
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Notice that x 2 c y 2 = 1 c y = y 1 − x 2 So d x d y = c y − x = (y 1 − x 2 ) − x = 1 − x 2 − x y = x 2 − 1 x y How to solve the ordinary differential equation 2xy \frac{dy}{dx} = x^2 y^2Consider the equation dy/dx = 1 x^2 y^2 2xy y_1 (x) = x is a particular solution of this equation y = y_1 1/v = x 1/v, Solve the resulting equation for the auxiliary function v and use the result to find a general solution of the given differential equation Such an equation isProblem 1 (8 pts) Let F(x, y, z) = (2xy sin z, x2 sin z e siny, xy cos z e cosy) (1) (4 pts) Is F conservative?
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Use separation of variables to solve the differential equation dy/dx 2xy^2 = 0 or equivalently written as y'2xy^2=0The steps to solving a DE by separationEquations Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations 1x^22xyy^2 so that you understand better51 Subtracting a fraction from a whole Rewrite the whole as a fraction using 4 as the denominator x2y 2xy (x2y 2xy) • 4 x2y 2xy = ————————— = ——————————————— 1 4 Equivalent fraction The fraction thus generated looks different but has the same value as the whole Common denominator
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求3x^2 2xyy^2=1上点 (1,2) 处的切线和法线方程： 解y=x^32x^2求导后有y′=3x²4x,所以x=1处的切点坐标为 (1,1),切线斜率为1,法线斜率为1注意切线法线的斜率之积等于1所以切线方程为y=x2,法线方程为y=xSolve ( dy(x))/( dx) = 2 x y(x)^2 Rewrite the equation 2 x y(x)^2 ( dy(x))/( dx) = 0 Let R(x, y) = 2 x y^2 and S(x, y) = 1 This is not an exact equation(x^2 1)y'' 2xy^1 = 0 (1) y(0) = 0 & y^1(0) = 0 y'' 2x/x^2 1 y^1 = 0 p = 2x/x^2 1, Q = 0 Here p and Q are both are analytic at x = 0, so x = 0 is an ordinary point Let y view the full answer
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